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SAT Math 10.1 Geometry and Measurement. How many cans of paint are needed?
SAT Math 11.2 Geometry and Measurement 178 Views
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Description:
SAT Math 11.2 Geometry and Measurement
- Geometry and Measurement / Transformations
- Product Type / SAT Math
- Mathematics and Statistics Assessment / Transformations and Symmetry
- Geometry / Understand similarity in terms of similarity transformations
- Similarity, Right Triangles, and Trigonometry / Understand similarity in terms of transformations
Transcript
- 00:02
Here’s your shmoop du jour, brought to you by translated lines.
- 00:06
Sometimes they're even foggier than Blurred Lines.
- 00:10
The line y = -2x + 4 is reflected over the y-axis, then translated down one unit and right two units.
- 00:18
What is its new y-intercept?
- 00:23
All right, so we’re talking about a line… on a graph…
Full Transcript
- 00:25
The line in question is y = -2x + 4.
- 00:28
Here’s our graph. Now…where would that line go?
- 00:32
Well, if y is zero, then x would have to be 2… so let’s draw a point on the x axis at (2,0).
- 00:39
If we want x to be zero…it would create a point of intersection at the y-axis at (0,4).
- 00:44
So…la la la… connecting the dots…
- 00:46
And…there’s our line.
- 00:48
Now…what does this problem want us to do with it?
- 00:51
Cast it into a lake and see if we can catch ourselves a trout?
- 00:54
Uh, no. Wrong kinda line. First it wants us to REFLECT the line across the y-axis.
- 01:00
Well, one point is right ON the y-axis, so… that guy ain’t goin’ nowhere.
- 01:04
In fact, the entire line is pretty much just going to pivot around that point, sorta like a hinge.
- 01:10
What about our other point, the one at (2,0)?
- 01:13
Yeah, that one gets reflected across, and becomes (-2,0).
- 01:16
So our new line looks like this: Last step… we need to translate… or shift…
- 01:21
the line down one unit, and two to the right.
- 01:24
This time we move both points…like so…
- 01:27
…and there’s our line’s final resting place.
- 01:29
So…where’s the new y-intercept?
- 01:31
Right here… at negative 1. And we have our answer.
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