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Algebraic Expressions Videos 17 videos
GED Math: Expression and Equations Drill 1, Problem 1. How much do the apples cost after tax?
Rigging your friend's scale so it looks like she's shedding the pounds: being a good friend, or being a total creeper? Translate a word problem int...
What do poetry and basic operations have in common? Watch this video to find out.
Translation into Mathematical Expressions 2538 Views
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Rigging your friend's scale so it looks like she's shedding the pounds: being a good friend, or being a total creeper? Translate a word problem into mathematical expressions and find out for yourself. (Our take: don't try this on any of your friends at home.)
Transcript
- 00:04
Translation into Mathematical Expressions, a la Shmoop.
- 00:09
Slash McFender, lead guitarist for the band Vibradeath is on his way to headline a concert.
- 00:15
Only one tiny problem...he forgot his guitar at home.
- 00:19
Thankfully, he has a thick jungle of chest hair which he can pluck to play some tunes.
- 00:28
Suppose that the frequency of vibration of Slash's chest hair is inversely proportional
Full Transcript
- 00:34
to the hair's length. If one of Slash's hairs is 0.7 inches long
- 00:43
and vibrates at 5 Hertz... ...what frequency, in Hertz, would a 0.5 inch
- 00:49
long chest hair have? We start by calling the frequency F and the
- 00:54
length of the chest hair L. The problem tells us that the formula for
- 00:59
the frequency of F is one over L. So F equals K over L, where K is the constant
- 01:07
of proportionality.
- 01:09
To find K, we can plug in what we know... ...Frequency is equal to 5 in this instance
- 01:17
and our length is 0.7. By multiplying both sides by 0.7...
- 01:28
...we see that K equals 3.5. So, plugging this new value into our formula...
- 01:41
... the frequency F of a 0.5 inch long chest hair must be...
- 01:51
...7 Hertz. The bad news is that Slash loves Vibradeath's
- 01:56
new sound so much that he has asked his bandmates to start going shirtless as well.
- 02:05
He's really redefining the term "hair band."
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