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Factoring Videos 19 videos
ACT Math Intermediate Algebra Drill 1, Problem 4. Solve for x based on the equation.
ACT Math Intermediate Algebra Drill 1, Problem 5. Can you simplify the expression?
ACT Math Intermediate Algebra Drill 2, Problem 1. Solve the equation.
SAT Math 8.6 Algebra and Functions 231 Views
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Description:
SAT Math 8.6 Algebra and Functions
Transcript
- 00:03
It's a bird! It's a plane! It's Shmooperman...guy!
- 00:09
Find the positive x-coordinate of the point where the graphs of the equations…
- 00:14
y = -2x squared - 6 y = -3x - 8 …intersect.
- 00:22
Okay…so this question is asking us to solve for two linear equations.
- 00:28
So, back in our old algebra days, we knew we had several methods that could help us do this…
Full Transcript
- 00:33
Solving by substitution…
- 00:35
…solving by elimination…
- 00:36
…or solving by graphing.
- 00:38
So in this case we can do any of these, but the easiest would be to just set them equal,
- 00:42
because…y equals y.
- 00:44
So we have -2x squared – 6 equals -3x – 8.
- 00:50
Now combine like terms and move everything to one side and we get:
- 00:54
2x squared – 3x – 2 = 0
- 00:59
…and that looks like a FACTORABLE quadratic equation.
- 01:03
Easiest way to solve this equation is to factor by grouping.
- 01:07
So if we split our -3x into x and -4x...
- 01:12
...we get 2x squared + x - 4x - 2 = 0.
- 01:19
This whole thing factors into x(2x + 1) - 2(2x + 1) = 0
- 01:27
Now we both have x and -2 multiplied by the quantity 2x + 1.
- 01:31
Do you know what we have to do next?
- 01:33
Factor out that 2x + 1.
- 01:36
Our final, fully factored equation is (2x + 1)(x-2) = 0.
- 01:44
Well, when x = -1/2 and 2... this equation is true.
- 01:48
Since the question asks for the positive x-coordinate, we'll take the positive 2.
- 01:54
So the answer is…2. That’s where they intersect.
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