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College Tour: New York University 13 Views
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Description:
If you're looking for a big school experience at one of the highest-ranked national universities, NYU might be your cup of tea. Then again, if you're really into cups of tea, Oxford might be more your style.
Transcript
- 00:04
And here's your Shmoop du jour, brought to you by spectators. [Man juggling balls on stage]
- 00:08
Because what’s the point of doing something cool if nobody’s watching?
- 00:12
Here’s today’s question.
- 00:14
In the neutralization reaction between CH3 CO OH and Na OH, which of the following ions
- 00:20
are spectator ions?
Full Transcript
- 00:26
And here are our potential answers.
- 00:28
Well, just like the spectators at a sporting event, spectator ions are key components. [Spectators watching a sporting game]
- 00:33
And just like the spectators at a sporting event, spectator ions don’t get to participate. [Ions on a football field]
- 00:38
When we write out a chemical reaction, spectator ions will appear on both sides, unchanged.
- 00:43
We need to examine this neutralization reaction in more detail so we can figure out who the
- 00:47
spectators are.
- 00:49
Unfortunately, these ones don’t identify themselves with foam fingers and face paint. [Spectator ions scribbled out]
- 00:54
The first thing we need to do is identify the stronger acid or base.
- 00:58
This species will dissociate completely and allow the neutralization reaction to proceed. [Acid and base stood side by side]
- 01:03
You probably don’t recognize acetic acid, CH3 CO OH, as an especially strong acid,
- 01:11
but hopefully you do recognize sodium hydroxide, NA OH, as a strong base. [NaOH dancing in a club]
- 01:16
If not, it’d probably be a good idea to review your list of strong bases.
- 01:22
Anyway, sodium hydroxide will completely dissociate in water, producing Na+
and OH- - 01:28
ions.
- 01:29
The OH- will take a proton from the acid, CH3 CO OH, and the overall reaction will yield [OH- taking a proton from an acid]
- 01:36
water and sodium acetate, as a salt.
- 01:39
This salt will dissociate in water. [Salt poured into a beaker]
- 01:41
Get all that?
- 01:42
Now let’s write this reaction in terms of ions for those species that dissociate.
- 01:47
So who are the spectators?
- 01:48
Well, we can identify spectators based on their lack of participation in this reaction.
- 01:53
The only ion that appears on both sides of the reaction, unchanged, is the sodium ion, [Sodium ions in reaction circled]
- 01:58
Na+, making our answer D. Now that was well worth watching, wasn’t
- 02:02
it?
- 02:03
What can we say?
- 02:04
We here at Shmoop like to put on a show. [People dancing in a street talent show]
- 02:05
…we just hope someone will come watch our tap routine next time.
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