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CAHSEE Math 6.4 Algebra I
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CAHSEE Math Algebra I: Drill 6, Problem 4. How much more ground can the Batmobile cover traveling at a speed of 75 mph in the same amount of time?

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CAHSEE Math 6.4 Algebra I 185 Views


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Description:

CAHSEE Math Algebra I: Drill 6, Problem 4. How much more ground can the Batmobile cover traveling at a speed of 75 mph in the same amount of time?

Language:
English Language

Transcript

00:03

Here’s a shmoopy question for ya…

00:05

Batman totally forgot he was supposed to be back in Gotham for a… business meeting in about an hour.

00:10

The Batmobile, traveling at an average of 60 mph, took a certain amount of time to cover

00:15

a distance of 80 miles.

00:17

How much more ground can it cover traveling at a speed of 75 mph in the same amount of time?

00:23

Here are the potential answers…

00:28

So… what is this question asking?

00:30

It’s a distance, rate and time problem which we have to just think through.

00:34

First, let’s put everything in the same units.

00:37

In this problem, we’re all miles… Batman wouldn’t dare fool around with kilometers.

00:41

That’s Alfred’s thing.

00:43

The Batmobile was going 60 miles an hour, so it can travel, well… 60 miles

00:47

in one hour… or 1 mile per minute.

00:49

So if it goes 80 miles, then it’s travelled 80 minutes.

00:53

But the key thing to glean here is that the Batmobile went for 80 minutes… or an hour

00:57

and 20 minutes… or 1.33 hours.

01:02

So now what if the Batmobile didn’t hit much traffic and was instead going 75 miles an hour?

01:07

To figure out how far it would have driven in that same amount of time, we multiply its

01:11

rate of 75 mph by 1.33 and we get… about 100 miles.

01:16

So the DIFFERENCE between the two distances is 20 miles.

01:22

Answer A. As in, "Alfred."

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