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Standard Algorithms Videos 20 videos

AP Computer Science 1.4 Standard Algorithms
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AP Computer Science 1.4 Standard Algorithms. How many times will mystery be called for mystery(n) for n > 1?

AP Computer Science 2.1 Standard Algorithms
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APCS: Standard Algorithms Drill 2, Problem 1. How much slower is InefficientSum than EfficientSum in the best case for an array of n elements?

AP Computer Science 2.5 Standard Algorithms
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In this computer science drill question, figure out which implementation will copy one array over to another.

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AP Computer Science 1.3 Standard Algorithms 173 Views


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Description:

AP Computer Science 1.3 Standard Algorithms. How many times will mystery be called for mystery(4), including the initial call?

Language:
English Language

Transcript

00:00

Thank you We sneak and here's your smug dooz your

00:05

featuring rijker jh in defined in the dictionary as now

00:10

Riker asians hope that helps How many times will mystery

00:14

he called for mystery for including the initial call Thinking

00:21

helps returns All right And here your potential answers bunching

00:25

up All right ready Pause and go I will Taking

00:30

a peek at the mystery function It looks like it'll

00:32

recur over itself If n does not equal zero one

00:38

or two All right well we're being asked how many

00:41

times mystery will get called if we give in the

00:45

value of floor like scooby doo All right well there's

00:49

really No better way for us to figure it out

00:52

And the old patent paper So from the top mystery

00:55

for that's one call if any cool Zero No no

00:59

If n equals one uh nope If n equals two

01:03

new well so we'll move along to this else case

01:07

and return mystery and minus one or three plus two

01:11

times mystery and minus two Better known as two Yeah

01:17

well that's Two more calls counting All right Well let's

01:22

take the low hanging fruit and handle that call to

01:24

mystery too It's an easy one that will simply return

01:28

to after having been caught by the if and equals

01:31

two statements The mystery three however won't get caught by

01:34

the ef zero one or two statements and we'll have

01:37

us calling mystery again two more times So we have

01:40

mystery and minus one which is to now will return

01:44

a two We've got that again that if statement catches

01:48

any shoes that it sees and mystery and minus two

01:52

is one and little return Ah one when caught by

01:56

the and equals one statement so looks like ryker shin

01:59

is over and we won't be making any more calls

02:03

to mystery making the answer five Well we sure are 00:02:07.235 --> [endTime] glad that's over and over and over over Yeah

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