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ACT Math: Coordinate Geometry Drill 1, Problem 1. Which inequality is expressed by the number line?
ACT Math: Coordinate Geometry Drill 5, Problem 2. Which of these three lines are parallel?
ACT Math: Coordinate Geometry Drill 1, Problem 2. Solve the inequality and determine which solution is shown on the number line.
ACT Math 3.2 Coordinate Geometry 304 Views
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Description:
ACT Math: Coordinate Geometry Drill 3, Problem 2. What is the slope of a line through the points given?
- Coordinate Geometry / Slope
- Product Type / ACT Math
- Foreign Language / Arabic Subtitled
- Foreign Language / Korean Subtitled
- Foreign Language / Spanish Subtitled
- Foreign Language / Chinese Subtitled
- Functions / Interpret expressions for functions in terms of the situation they model
- Geometry / Translate between the geometric description and equation for a conic section
- Properties, Measurement, and Dimension / Translate between the geometric description and the equation for a conic section
- Coordinate Geometry / Slope
Transcript
- 00:02
For a good time, solve this shmoopy question...
- 00:05
What is the slope of the line through 4, 7 and -2, 6?
- 00:09
And here are your options...
- 00:12
The standard equation for point slope lines
- 00:16
is Y equals MX plus B and we can get M
Full Transcript
- 00:20
by subtracting two points on a graph so in this case check out the points here
- 00:24
on the graph.
- 00:25
4, 7 and -2, 6. The points live here and here
- 00:30
and we can draw a line through them in a slope is here. Line goes a little bit
- 00:34
upward...so double check ourselves we know it's gonna have to have a positive slope
- 00:39
so we can immediately reject C, D and E So in this case
- 00:43
we just subtract the points and put them in the form Y
- 00:46
over X. So take the 7 of the 4, 7 point
- 00:50
and subtract 6 from it. We get 1 in the numerator
- 00:54
now get the x-coordinate. We have 4
- 00:57
minus -2 which is just adding 2
- 01:00
to get 6. So that's slope of 1 over 6. Here it is.
- 01:05
Answer A as in "Abracadabra."
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