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AP Physics 1: 2.3 System Interactions and Changes 193 Views
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Description:
AP Physics 1: System Interactions and Changes Drill 2, Problem 3. What is the acceleration of the box?
Transcript
- 00:00
Thank you We sneak and here's your shmoop du jour
- 00:05
Brought to you by static friction Some materials have a
- 00:08
low coefficient of friction And with other materials like say
- 00:12
us in our bed almost no amount of force can
- 00:15
make a move All right twenty kilogram boxes dropped onto
Full Transcript
- 00:18
his surface with a static friction coefficient of zero point
- 00:21
five in a kinetic friction coefficient of zero point two
- 00:24
a force of eighty newtons is applied to the box
- 00:28
What is the acceleration of the box And here the
- 00:32
potential answers in meters per second squared All right well
- 00:35
we here at shmoop love information We crave it but
- 00:39
there is such a thing as too much information For
- 00:42
example one time we told a friend that we still
- 00:44
sleepin batman pajamas And that was definitely a t m
- 00:47
i And this question wealth a little tricky because it
- 00:50
has too much information also but let's tackle the math
- 00:53
First first thing we have to do is get this
- 00:55
box moving And to do that we need to overcome
- 00:58
the force of static friction Well to calculate that force
- 01:01
we just multiply the normal force in this case mass
- 01:04
Times Gravity by the coefficient of friction so here's the
- 01:07
equation Once we have the numbers we need we plug
- 01:11
him in and find that the force of friction is
- 01:13
one hundred newtons Since the force acting on the box
- 01:17
is only eighty new queens the box is going nowhere
- 01:20
fast so the correct answer is just option a zero
- 01:22
meters per second squared and sense is not gonna budge
- 01:26
The kinetic friction coefficient doesn't matter No movement equals no
- 01:30
kinetic friction That's What we mean by t m i
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